Kunci Jawaban Matematika Kelas 7 Halaman 77-81 Kurikulum Merdeka Menyederhanakan Bentuk Linear

= -x - 3

(3) = (-4a + 9) - (a + 3)

= (-4a + 9) + (-a - 3)

= -5a + 6

(4) = (5a + 6) - (-2a + 6)

= (5a + 6) + (2a - 6)

= 7a

(5) = (7 - x) - (2x + 8)

= (7 - x) + (-2x - 8)

= -3x - 1

(6)= (⅓x - 2) - (½x - 5)

= (⅓x - 2) + (-½x + 5)

= ⅓x - ½x - 2 + 5

= 2/6x - 3/6x + 3

= -1/6x + 3

Baca juga: Kunci Jawaban Matematika Kelas 9 Halaman 179, 180, 181, 182 Latihan 3.4 Dilatasi

Soal nomor 3

(1) 6x x 2

(2) (-7) x 2y

(3) (-3a) x 4

(4) -b x (-9)

(5) 10 x 0,8x

(6) ⅔a x 6

Kunci Jawaban:

(1)= 6x x 2

= 12x

(2) = (-7) x 2y

= (-7) x 2 x y

= -14y

(3= (-3a) x 4

= (-3) x a x 4

= -12a

(4) = -b x (-9)

= 9b

(5)= 10 x 0,8 x x

= 8x

(6) = ⅔a x 6

= ⅔ x a x 6

= 4a

Soal nomor 4, Sederhanakanlah.

(1) 5 (x + 2)

(2) -2 (4x + 5

(3) (1 - 6x) x 3

(4) (a - 4) x (-6)

(5) - (-9x + 8)

(6) ⅔ (9y + 6)

Kunci Jawaban:

(1) = 5 (x + 2)

= (5 x x) + (5 x 2)

= 5x + 10

(2) = -2 (4x + 5)

= (-2 x 4x) + (-2 x 5)

= -8x - 10

(3) = (1 - 6x) x 3

= 1 x 3 + (-6x) x 3

= 3 - 18x

(4) = (a - 4) x (-6)

= a x (-6) + (-4) x (-6)

= -6a + 24

(5) = - (-9x + 8)

= -1 x (-9x) + (-1) x 8

= 9x - 8

(6)= ⅔ (9y + 6)

= ⅔ x 9y + ⅔ x 6

= 6y + 4

Soal nomor 5

1. 3x + 1 / 2 x 4

2. 12 x x - 3 / 4

Kunci Jawaban

1. = 3x + 1 / 2 x 4

= (3x + 1) x 2

= 3x x 2 + 1 x 2

= 6x + 2

2. = 12 x x - 3 / 4

= 3 (x - 3)

= 3 x x + 3 x (-3)

= 3x + (-9)

Baca juga: Kunci Jawaban Matematika Kelas 7 Halaman 72 dan 73 Kurikulum Merdeka Substitusi Bentuk Aljabar

Soal nomor 6

(1) 8x : 2

(2) 12x : (-4)

(3) -10x : (-5)

(4) -a : 5

(5) 9x : 12

(6) 15x : (-3/2)

Kunci Jawaban:

(1)= 8x : 2

= 8x x ½

= 4x

(2) = 12x : (-4)

= 12x x (-¼)

= -3x

(3)= -10x : (-5)

= -10x x (-1/5)

= 2x

(4) = -a : 5

= -1 x a x 1/5

= -1/5a

(5)= 9x : 12

= 9x x 1/12

= 9/12x

= 3/4x

(6) = 15x : (-3/2)

= 15x x (-2/3)

= -30/3x

= -10x

Soal nomor 7

(1) (2x + 6) : 2

(2) (12a - 8) : (-4)

(3) (10x - 5) : 5/2

Kunci Jawaban:

(1) = (2x + 6) : 2

= (2x + 6) x ½

= 2x x ½ + 6 x ½

= x + 3

(2) = (12a - 8) : (-4)

= (12a - 8) x (-¼)

= 12a x (-¼) + (-8) x (-¼)

= -3a + 2

(3) = (10x - 5) : 5/2

= (10x - 5) x 2/5

= 10x x 2/5 + (-5) x 2/5

= 4x - 2

Soal nomor 8

Ilzar mengubah (8x – 3) : 2 ke dalam pecahan seperti ditunjukkan di samping ini.

Apakah yang dilakukan Ilzar benar?

Koreksilah kesalahannya jika ada.

Kunci Jawaban:

Tidak benar

=(8x-3) : 2

= 8x-3/2

= 8x/2 - 3/2

= 4x - 3/2

Soal nomor 9

Sederhanakanlah.

(1) (6x + 1) + 3(x + 2)

(2) 2(-a + 6) + 4(a – 3)

(3) -3(3x – 5) + 7(2x – 1)

(4) 2(a + 5) – 8(a + 1)

(5) 6(x – 2) – 2(3x – 7)

(6) -(a – 8) – 5(-2a + 4)

Kunci Jawaban:

(1) = (6x + 1) + 3(x + 2)

= 6x + 1 + 3x + 6

= 9x + 7

(2) = 2(-a + 6) + 4(a - 3)

= -2a + 12 + 4a - 12

= 2a

(3) = -3(3x - 5) + 7(2x - 1)

= -9x + 15 + 14x - 7

= 5x + 8

(4) = 2(a + 5) - 8(a + 1)

= 2a + 10 - 8a - 8

= -6a + 2

(5) = 6(x - 2) - 2(3x - 7)

= 6x - 12 - 6x + 14

= 2

(6) = - (a - 8) - 5(-2a + 4)

= -a + 8 + 10a - 20

= 9a - 12

Soal nomor 10

Sederhanakanlah.

(1) ½(6x + 4) + (6x - 3)

(2) ⅔(9a - 6) - ½(2a - 10)

Kunci Jawaban:

(1) = ½(6x + 4) + (6x - 3)

= 3x + 2 + 6x - 3

= 9x - 1

(2)= ⅔(9a - 6) - ½(2a - 10)

= 6a - 4 - a + 5

= 5a + 1

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